1876 Rhode Island gubernatorial election
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The 1876 Rhode Island gubernatorial election was held on April 5, 1876. Incumbent Republican governor Henry Lippitt defeated Prohibition Party nominee Albert C. Howard and Democratic nominee William B. Beach.
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April 5, 1876
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 County results Lippitt: 40â50% 50â60% Howard: 30â40% 40â50% | |||||||||||||||||||||||||
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Since no candidate received a majority in the popular vote, Lippitt was elected by the Rhode Island General Assembly per the state constitution.
General election
Candidates
Major party candidates
- Henry Lippitt, Republican[1]
- William B. Beach, Democratic
Other candidates
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Henry Lippitt (incumbent) | 8,689 | 45.64% | ||
| Prohibition | Albert C. Howard | 6,733 | 35.37% | ||
| Democratic | William B. Beach | 3,599 | 18.91% | ||
| Scattering | 16 | 0.08% | |||
| Majority | 1,956 | 10.27% | |||
| Turnout | 19,037 | ||||
| Republican hold | Swing | ||||
Legislative election
As no candidate received a majority of the vote, the Rhode Island General Assembly was required to decide the election, choosing among the top two vote-getters, Lippitt and Howard. The legislative election was held on May 30, 1876.
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Henry Lippitt | 74 | 71.84% | |
| Prohibition | Albert C. Howard | 29 | 28.16% | |
| Turnout | 103 | |||
Notes
- 20th Century sources variously describe Howard as a "National Republican", "Republican and Prohibitionist", "National Republican and Prohibitionist".
