1884 United States presidential election in Arkansas
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The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose seven electors to the Electoral College, which selected the president and vice president.
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November 4, 1884
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 County results
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Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.
Results
| 1884 United States presidential election in Arkansas[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 72,734 | 57.83% | 7 | 100.00% | ||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 51,198 | 40.70% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 1,847 | 1.47% | 0 | 0.00% | ||
| Total | 125,779 | 100.00% | 7 | 100.00% | ||||
