1886 New York City mayoral election
From Wikipedia, the free encyclopedia
An election for Mayor of New York City was held on November 2, 1886.
November 2, 1886
| |||||||||||||||||||||
| |||||||||||||||||||||
Ward results Hewitt: 30â40% 40â50% 50â60% 60â70% George: 30â40% 40â50% Roosevelt: 40â50% 50â60% | |||||||||||||||||||||
| |||||||||||||||||||||
Candidates included four-term former state assemblyman Theodore Roosevelt, author Henry George, and five-term U.S. Representative Abram Hewitt.[1] Roosevelt, at age 28,[1] would have been the youngest mayor in New York City history had he been elected.[2][3]
The election saw many Republican voters swing their support to Hewitt.[1][4]
Campaign
- Henry George, political economist and tax reformer (United Labor)
- Abram Hewitt, U.S. Representative and former chair of the Democratic National Committee (Democratic)
- Theodore Roosevelt, former Assemblyman from the Upper East Side (Republican)
- William T. Wardwell (Prohibition)
Daniel De Leon, the future leader of the Socialist Labor Party of America, campaigned for George.[5]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Abram Hewitt | 90,552 | 41.23 | |
| United Labor | Henry George | 68,110 | 31.01 | |
| Republican | Theodore Roosevelt | 60,435 | 27.52 | |
| Prohibition | William T. Wardwell | 532 | 0.24 | |
| Democratic gain from nonpartisan candidate | ||||