1886 Rhode Island gubernatorial election
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The 1886 Rhode Island gubernatorial election was held on April 7, 1886. Incumbent Republican George P. Wetmore defeated Democratic nominee Amasa Sprague with 53.36% of the vote.
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April 7, 1886
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Wetmore: 40â50% 50â60% 60â70% 70â80% Sprague: 40â50% 50â60% Tie: 40â50% | |||||||||||||||||||||
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General election
Candidates
Major party candidates
- George P. Wetmore, Republican
- Amasa Sprague, Democratic
Other candidates
- George H. Slade, Prohibition
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | George P. Wetmore (incumbent) | 14,340 | 53.36% | ||
| Democratic | Amasa Sprague | 9,944 | 37.00% | ||
| Prohibition | George H. Slade | 2,585 | 9.62% | ||
| Scattering | 6 | 0.02% | |||
| Majority | 4,396 | 16.36% | |||
| Turnout | 26,875 | ||||
| Republican hold | Swing | ||||