1889 Rhode Island gubernatorial election

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The 1889 Rhode Island gubernatorial election was held on April 3, 1889. Democratic nominee John W. Davis received 49.38% of the vote and the Republican nominee Herbert W. Ladd 39.13%. With no candidate attaining a majority of the vote it was decided by the Rhode Island General Assembly.[1] In the same election, the Republican Party had won a small majority in the legislature and selected Ladd as governor.[2][3]

Quick facts Nominee, Party ...
1889 Rhode Island gubernatorial election

← 1888
April 3, 1889
1890 â†’
 
Nominee Herbert W. Ladd John W. Davis James Chace
Party Republican Democratic Independent
Popular vote 16,870 21,289 3,596
Percentage 39.13% 49.38% 8.34%

Ladd:      40–50%      50–60%      60–70%
Davis:      30–40%      40–50%      50–60%

Governor before election

Royal C. Taft
Democratic

Elected Governor

Herbert W. Ladd
Republican

Close

General election

Candidates

Major party candidates

  • Herbert W. Ladd, Republican
  • John W. Davis, Democratic

Other candidates

  • James Chace, Independent
  • Harrison H. Richardson, Prohibition

Results

More information Party, Candidate ...
1889 Rhode Island gubernatorial election[4]
Party Candidate Votes % ±%
Republican Herbert W. Ladd 16,870 39.13%
Democratic John W. Davis 21,289 49.38%
Independent James Chace 3,596 8.34%
Prohibition Harrison H. Richardson 1,346 3.12%
Majority 4,419
Turnout
Republican hold Swing
Close

References

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