1890 Kansas gubernatorial election

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The 1890 Kansas gubernatorial election was held on November 4, 1890. Incumbent Republican Lyman U. Humphrey defeated People's Party nominee John F. Willits with 39.05% of the vote.

Quick facts Nominee, Party ...
1890 Kansas gubernatorial election

← 1888
November 4, 1890
1892 â†’
 
Nominee Lyman U. Humphrey John F. Willits Charles L. Robinson
Party Republican Populist Democratic
Popular vote 115,024 106,945 71,357
Percentage 39.05% 36.31% 24.23%

County results
Humphrey:      30–40%      40–50%      50–60%      60–70%
Willits:      30–40%      40–50%      50–60%
Robinson:      30–40%      40–50%      50–60%      60–70%

Governor before election

Lyman U. Humphrey
Republican

Elected Governor

Lyman U. Humphrey
Republican

Close

General election

Candidates

Major party candidates

  • Lyman U. Humphrey, Republican
  • Charles L. Robinson, Democratic

Other candidates

  • John F. Willits, People's
  • A. M. Richardson, Prohibition

Results

More information Party, Candidate ...
1890 Kansas gubernatorial election[1]
Party Candidate Votes % ±%
Republican Lyman U. Humphrey (incumbent) 115,024 39.05%
Populist John F. Willits 106,945 36.31%
Democratic Charles L. Robinson 71,357 24.23%
Prohibition A. M. Richardson 1,230 0.42%
Majority 8,079
Turnout
Republican hold Swing
Close

References

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