1890 New Hampshire gubernatorial election

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The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

Quick facts Nominee, Party ...
1890 New Hampshire gubernatorial election

← 1888
November 4, 1890
1892 â†’
 
Nominee Hiram A. Tuttle Charles H. Amsden
Party Republican Democratic
Popular vote 42,479 42,386
Percentage 49.26% 49.15%

Tuttle:      40-50%      50–60%      60–70%      70–80%      80–90%
Amsden:      40-50%      50–60%      60–70%      70–80%      80–90%      >90%
Tie:      40-50%      50%

Governor before election

David H. Goodell
Republican

Elected Governor

Hiram A. Tuttle
Republican

Close

General election

Candidates

Major party candidates

  • Hiram A. Tuttle, Republican
  • Charles H. Amsden, Democratic

Other candidates

  • Josiah M. Fletcher, Prohibition

Results

More information Party, Candidate ...
1890 New Hampshire gubernatorial election[1]
Party Candidate Votes % ±%
Republican Hiram A. Tuttle 42,479 49.26%
Democratic Charles H. Amsden 42,386 49.15%
Prohibition Josiah M. Fletcher 1,343 1.56%
Majority 93
Turnout
Republican hold Swing
Close

References

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