1891 Canterbury colonial election re-count
By-election in New South Wales, Australia
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In September 1891 the Elections and Qualifications Committee conducted a re-count of the 1891 Canterbury election. There were 4 seats available. Joseph Carruthers (Free Trade) had been comfortably re-elected at the head of the poll with 7,231 votes, 19.8%. The following 4 candidates were separated by 105 votes, with John Wheeler (Free Trade) defeating James Eve (Ind. Free Trade) for the final seat with a margin of 5 votes. The next best candidate, John Grant (Labour) was a further 487 behind, with 3,857 votes, 10.6%.[1]
The committee declared that John Wheeler (Free Trade) had not been elected the member for Canterbury, however no by-election was conducted. Instead the committee declared that James Eve (Ind. Free Trade) based on its own count of the result.[1][2]
Dates
| Date | Event |
|---|---|
| 17 Juneâ 1891 | 1891 Canterbury election |
| 24 June 1891 | Petition lodged by James Eve.[3] |
| 14 July 1891 | John Wheeler sworn in as member for Canterbury |
| 16 July 1891 | Elections and Qualifications Committee appointed.[2] |
| 29 July 1864 | Petition referred to the Elections and Qualifications Committee.[2] |
| 2 September 1891 | Elections and Qualifications Committee declared that James Eve had been elected.[2] |
Result
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Free Trade | Joseph Carruthers (re-elected 1) | N/A | |||
| Labour | Thomas Bavister (elected 2) | 4,453 | 12.19 | +0.01 | |
| Labour | Cornelius Danahey (elected 3) | 4,363 | 11.99 | +0.03 | |
| Ind. Free Trade | James Eve (elected 4) | 4,349 | 11.92 | +0.02 | |
| Free Trade | John Wheeler (defeated) | 4,344 | 11.90 | â0.02 | |
| Total formal votes | 36,491 | 99.30 | â0.02 | ||
| Informal votes | 258[a] | 0.70 | +0.02 | ||
| Turnout | 10,279 | 54.96 | '"`UNIQâârefâ00000011âQINU`"' | ||
| Ind. Free Trade gain 1 from Free Trade | |||||
See also
Notes
- Calculated on the assumption that the total number of votes did not change.