1891 Iowa gubernatorial election
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The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Hiram C. Wheeler with 49.40% of the vote.
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November 3, 1891
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 County results Boies: 40â50% 50â60% 60â70% 70â80% Wheeler: 40â50% 50â60% 60â70% Westfall: 30â40% | |||||||||||||||||
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General election
Candidates
Major party candidates
- Horace Boies, Democratic
- Hiram C. Wheeler, Republican
Other candidates
- A. J. Westfall, People's
- Isaac T. Gibson, Prohibition
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | Horace Boies (incumbent) | 207,594 | 49.40% | ||
| Republican | Hiram C. Wheeler | 199,381 | 47.45% | ||
| Populist | A. J. Westfall | 12,303 | 2.93% | ||
| Prohibition | Isaac T. Gibson | 915 | 0.22% | ||
| Majority | 8,213 | ||||
| Turnout | |||||
| Democratic hold | Swing | ||||