1892 Rhode Island gubernatorial election
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The 1892 Rhode Island gubernatorial election was held on April 6, 1892. Republican nominee Daniel Russell Brown defeated Democratic nominee William T. C. Wardwell with 50.22% of the vote.
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April 6, 1892
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Brown: 40â50% 50â60% 60â70% 80-90% Wardwell: 40â50% 50â60% | |||||||||||||||||
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General election
Candidates
Major party candidates
- Daniel Russell Brown, Republican
- William T. C. Wardwell, Democratic
Other candidates
- Alexander Gilbert, Prohibition
- Franklin E. Burton, People's
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Daniel Russell Brown | 27,461 | 50.22% | ||
| Democratic | William T. C. Wardwell | 25,433 | 46.51% | ||
| Prohibition | Alexander Gilbert | 1,598 | 2.92% | ||
| Populist | Franklin E. Burton | 187 | 0.34% | ||
| Majority | 2,028 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||