1892 United States presidential election in Delaware

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

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1892 United States presidential election in Delaware

← 1888 November 8, 1892 1896 â†’

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Adlai Stevenson I Whitelaw Reid Electoral vote 3 0 Popular vote 18,581 18,077 Percentage 49.90% 48.55%

County Results Cleveland   40–50%   50–60%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

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Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Despite reclaiming the presidency, Cleveland performed much worse in Delaware than he did in his 1888 re-election bid. The State shifted 10 points for Benjamin Harrison, voting for Cleveland by only 1.4 percentage points. This would be one of four states where Harrison outperformed his initial run for the presidency in 1888. The other states were New Hampshire, Georgia and, South Carolina.

This is the last election in which Delaware voted Democratic until 1912; and the last in which it voted Democratic two or more consecutive times until 1940.