1894 Rhode Island gubernatorial election
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The 1894 Rhode Island gubernatorial election was held on April 4, 1894. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 53.15% of the vote.
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April 4, 1894
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Brown: 40â50% 50â60% 60â70% 70â80% 80-90% Baker: 40â50% | |||||||||||||||||
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General election
Candidates
Major party candidates
- Daniel Russell Brown, Republican
- David S. Baker, Democratic
Other candidates
- Henry B. Metcalf, Prohibition
- Charles G. Baylor, Socialist Labor
- Henry A. Burlingame, People's
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Daniel Russell Brown (incumbent) | 29,157 | 53.15% | ||
| Democratic | David S. Baker | 22,650 | 41.29% | ||
| Prohibition | Henry B. Metcalf | 2,241 | 4.09% | ||
| Socialist Labor | Charles G. Baylor | 592 | 1.08% | ||
| Populist | Henry A. Burlingame | 223 | 0.41% | ||
| Majority | 6,507 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||