1896 Georgia gubernatorial election

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The 1896 Georgia gubernatorial election was held on October 7, 1896, in order to elect the Governor of Georgia. Democratic nominee and incumbent Governor William Yates Atkinson defeated People's Party nominee Seaborn Wright.[1]

Quick facts Nominee, Party ...
1896 Georgia gubernatorial election

← 1894
October 7, 1896
1898 â†’
 
Nominee William Yates Atkinson Seaborn Wright
Party Democratic Populist
Popular vote 123,206 85,981
Percentage 58.90% 41.10%

County results
Atkinson:      50–60%      60–70%      70–80%      80–90%      >90%
Wright:      50–60%      60–70%      70–80%      80–90%

Governor before election

William Yates Atkinson
Democratic

Elected Governor

William Yates Atkinson
Democratic

Close

General election

On election day, October 7, 1896, Democratic nominee William Yates Atkinson won re-election with a margin of 37,225 votes against his opponent People's Party nominee Seaborn Wright, thereby holding Democratic control over the office of Governor. Atkinson was sworn in for his second term on October 29, 1896.[2]

Results

More information Party, Candidate ...
Georgia gubernatorial election, 1896
Party Candidate Votes %
Democratic William Yates Atkinson (incumbent) 123,206 58.90
Populist Seaborn Wright 85,981 41.10
Total votes 209,187 100.00
Democratic hold
Close

References

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