1896 Missouri Attorney General election
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The 1896 Missouri Attorney General election was held on November 3, 1896, in order to elect the attorney general of Missouri. Democratic nominee Edward Coke Crow defeated Republican nominee John Kennish, People's nominee Frank E. Richey, Prohibition nominee George E. Bowling and National Democratic nominee Nicholas D. Thurmond.[1]
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November 3, 1896
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General election
On election day, November 3, 1896, Democratic nominee Edward Coke Crow won the election by a margin of 35,899 votes against his foremost opponent Republican nominee John Kennish, thereby retaining Democratic control over the office of attorney general. Crow was sworn in as the 23rd attorney general of Missouri on January 11, 1897.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Edward Coke Crow | 340,585 | 50.58 | |
| Republican | John Kennish | 304,686 | 45.25 | |
| Populist | Frank E. Richey | 24,062 | 3.56 | |
| Prohibition | George E. Bowling | 2,053 | 0.31 | |
| National Democratic | Nicholas D. Thurmond | 2,008 | 0.30 | |
| Total votes | 673,394 | 100.00 | ||
| Democratic hold | ||||