1902 Minnesota Attorney General election
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The 1902 Minnesota Attorney General election was held on November 4, 1902, in order to elect the attorney general of Minnesota. Republican nominee and incumbent attorney general Wallace B. Douglas defeated Democratic nominee Frank D. Larrabee.[1]
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November 4, 1902
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General election
On election day, November 4, 1902, Republican nominee Wallace B. Douglas won re-election by a margin of 75,224 votes against his opponent Democratic nominee Frank D. Larrabee, thereby retaining Republican control over the office of attorney general. Douglas was sworn in for his third term on January 7, 1903.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Wallace B. Douglas (incumbent) | 165,744 | 64.68 | |
| Democratic | Frank D. Larrabee | 90,520 | 35.32 | |
| Total votes | 256,264 | 100.00 | ||
| Republican hold | ||||