1904 United States presidential election in Rhode Island

The 1904 United States presidential election in Rhode Island took place on November 8, 1904, as part of the 1904 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

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1904 United States presidential election in Rhode Island

← 1900 November 8, 1904 1908 â†’

Nominee Theodore Roosevelt Alton B. Parker Party Republican Democratic Home state New York New York Running mate Charles W. Fairbanks Henry G. Davis Electoral vote 4 0 Popular vote 41,605 24,839 Percentage 60.60% 36.18%

County Results Municipality Results Roosevelt   50–60%   60–70%   70–80%   80–90%   90–100% Bryan   50–60%

President before election Theodore Roosevelt Republican Elected President Theodore Roosevelt Republican

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Rhode Island overwhelmingly voted for the Republican nominee, President Theodore Roosevelt, over the Democratic nominee, former Chief Judge of New York Court of Appeals Alton B. Parker. Roosevelt won Rhode Island by a margin of 24.42%.