1906 Rhode Island gubernatorial election
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The 1906 Rhode Island gubernatorial election was held on November 6, 1906. Democratic nominee James H. Higgins defeated incumbent Republican George H. Utter with 49.92% of the vote.
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November 6, 1906
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Higgins: 40â50% 50â60% Utter: 40â50% 50â60% 60â70% 70â80% 80-90% | |||||||||||||||||
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General election
Candidates
Major party candidates
- James H. Higgins, Democratic
- George H. Utter, Republican
Other candidates
- Bernan E. Helme, Prohibition
- Warren A. Carpenter, Socialist
- David J. Moran, Socialist Labor
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | James H. Higgins | 33,195 | 49.92% | ||
| Republican | George H. Utter (incumbent) | 31,877 | 47.94% | ||
| Prohibition | Bernan E. Helme | 714 | 1.07% | ||
| Socialist | Warren A. Carpenter | 395 | 0.59% | ||
| Socialist Labor | David J. Moran | 320 | 0.48% | ||
| Majority | 1,318 | ||||
| Turnout | |||||
| Democratic gain from Republican | Swing | ||||