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1910 Vermont gubernatorial election

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The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.

Quick facts Nominee, Party ...
1910 Vermont gubernatorial election
← 1908
September 6, 1910 (1910-09-06)
1912 â†’
 
Nominee John A. Mead Charles D. Watson
Party Republican Democratic
Popular vote 35,263 17,425
Percentage 64.2% 31.7%
Mead:      40–50%      50–60%      60–70%      70–80%      80–90%      90-100%
Watson:      40–50%      50–60%      60–70%
No Vote/Data:      
Governor before election

George H. Prouty
Republican

 Elected Governor

John A. Mead
Republican

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Marshall J. Hapgood, who ran a quixotic campaign for the Republican gubernatorial nomination, filed Vermont's first-ever campaign finance report, which indicated that he spent $103.76 (equivalent to $3,585 in 2025).[2]

Results

More information Party, Candidate ...
1910 Vermont gubernatorial election[3]
Party Candidate Votes % ±%
Republican John A. Mead 35,263 64.2
Democratic Charles D. Watson 17,425 31.7
Prohibition Edwin R. Towle 1,044 1.9
Socialist Chester E. Ordway 1,055 1.9
N/A Other 141 0.3
Total votes '54,928' '100'
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