1910 Vermont gubernatorial election
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The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.
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September 6, 1910
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Mead: 40â50% 50â60% 60â70% 70â80% 80â90% 90-100% Watson: 40â50% 50â60% 60â70% No Vote/Data: | |||||||||||||||||
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Marshall J. Hapgood, who ran a quixotic campaign for the Republican gubernatorial nomination, filed Vermont's first-ever campaign finance report, which indicated that he spent $103.76 (equivalent to $3,585 in 2025).[2]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | John A. Mead | 35,263 | 64.2 | ||
| Democratic | Charles D. Watson | 17,425 | 31.7 | ||
| Prohibition | Edwin R. Towle | 1,044 | 1.9 | ||
| Socialist | Chester E. Ordway | 1,055 | 1.9 | ||
| N/A | Other | 141 | 0.3 | ||
| Total votes | '54,928' | '100' | |||
