1918 Rhode Island gubernatorial election
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The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.
November 5, 1918
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Beeckman: 40â50% 50â60% 60â70% 70â80% 80â90% >90% Archambault: 40â50% 50â60% | |||||||||||||||||
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General election
Candidates
Major party candidates
- Robert Livingston Beeckman, Republican
- Alberic A. Archambault, Democratic
Other candidates
- Ernest Sherwood, Socialist
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Robert Livingston Beeckman (incumbent) | 42,682 | 53.11% | ||
| Democratic | Alberic A. Archambault | 36,031 | 44.84% | ||
| Socialist | Ernest Sherwood | 1,648 | 2.05% | ||
| Majority | 6,651 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||