1918 Vermont gubernatorial election
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The 1918 Vermont gubernatorial election took place on November 5, 1918. Incumbent Republican Horace F. Graham, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Percival W. Clement defeated Democratic candidate William B. Mayo to succeed him.
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November 5, 1918
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Clement: 40â50% 50â60% 60â70% 70â80% 80â90% 90-100% Mayo: 40â50% 50â60% 60â70% 80â90% Tie: 50% No Vote/Data: | |||||||||||||||||
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Republican primary
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Percival W. Clement | 12,060 | 37.0 | ||
| Republican | Charles H. Darling | 11,403 | 35.0 | ||
| Republican | Frank E. Howe | 9,122 | 28.0 | ||
| Republican | Other | 2 | 0.0 | ||
| Total votes | '32,587' | '100' | |||
Democratic primary
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | William B. Mayo | 2,486 | 99.9 | ||
| Democratic | Other | 4 | 0.1 | ||
| Total votes | '2,490' | '100' | |||
General election
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Percival W. Clement | 28,358 | 67.0 | ||
| Democratic | William B. Mayo | 12,517 | 29.6 | ||
| Progressive | William B. Mayo | 1,342 | 3.1 | ||
| Total | William B. Mayo | 13,859 | 32.7 | ||
| N/A | Other | 106 | 0.3 | ||
| Total votes | '42,323' | '100' | |||
