1925 Paris–Roubaix
Cycling race
From Wikipedia, the free encyclopedia
The 1925 Paris–Roubaix was the 26th edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 12 April 1925 and stretched 260 km (162 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Félix Sellier from Belgium.[2]
Dates12 April 1925
Stages1
Distance260 km (160 mi)
Winning time9h 16' 32"
| Race details | ||||||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Dates | 12 April 1925 | |||||||||
| Stages | 1 | |||||||||
| Distance | 260 km (160 mi) | |||||||||
| Winning time | 9h 16' 32" | |||||||||
| Results | ||||||||||
| ||||||||||
Results
| Rank | Cyclist | Time |
|---|---|---|
| 1 |  Félix Sellier (BEL) |
9h 16' 32″ |
| 2 |  Pietro Bestetti (ITA) |
+0' 00″ |
| 3 | Jules Van Hevel (BEL) |
+0' 00″ |
| 4 | Pietro Linari (ITA) |
+0' 00″ |
| 5 |  Heiri Suter (SUI) |
+0' 00″ |
| 6 | Adelin Benoit (BEL) |
+0' 00″ |
