1926 Maryland Attorney General election
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The 1926 Maryland attorney general election was held on November 2, 1926, in order to elect the attorney general of Maryland. Democratic nominee and incumbent attorney general Thomas H. Robinson defeated Republican nominee and former Mayor of Baltimore William Frederick Broening and Socialist nominee John A. Orman.[1]
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November 2, 1926
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 County results Robinson: 50â60% 60â70% Broening: 50â60% 60â70% | |||||||||||||||||
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General election
On election day, November 2, 1926, Democratic nominee Thomas H. Robinson won re-election by a margin of 36,282 votes against his foremost opponent Republican nominee William Frederick Broening, thereby retaining Democratic control over the office of attorney general. Robinson was sworn in for his second term on January 3, 1927.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Thomas H. Robinson (incumbent) | 184,337 | 54.97 | |
| Republican | William Frederick Broening | 148,055 | 44.15 | |
| Socialist | John A. Orman | 2,951 | 0.88 | |
| Total votes | 335,343 | 100.00 | ||
| Democratic hold | ||||