1940 USSR Chess Championship
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| 12th Soviet Chess Championship (1940) | |
|---|---|
| Location | Moscow |
| Champion | |
| Andor Lilienthal Igor Bondarevsky | |
The 1940 Soviet Chess Championship was the 12th edition of USSR Chess Championship. Held from 5 September to 3 October 1940 in Moscow. The tournament was won by Andor Lilienthal and Igor Bondarevsky. Twenty of the Soviet Union's strongest masters competed in the final, six of whom qualified in the semifinals in Kiev earlier that year: Eduard Gerstenfeld, Mark Stolberg, Igor Bondarevsky, Iosif Rudakovsky, Alexander Konstantinopolsky and Peter Dubinin. The remaining invitations went to the Soviet chess elite. Botvinnik did his worst championship, only drawing in 5th/6th position, losing matches to both winners. This championship marked the debut of Paul Keres (4th) and the future world champion Vassily Smyslov (3rd). USSR had expanded its territory in 1939-40, incorporating the Baltic states, which meant that the strong masters Paul Keres from Estonia and Vladimir Petrov from Latvia were able to participate. In 1941, the top six played a competition called Absolute Championship of Soviet Union, ending with Botvinnik's victory.[1]
