1948 Davis Cup America Zone

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The America Zone was one of the two regional zones of the 1948 Davis Cup.

4 teams entered the America Zone, with the winner going on to compete in the Inter-Zonal Final against the winner of the Europe Zone.[1] Australia defeated Mexico in the final, and went on to face Czechoslovakia in the Inter-Zonal Final.[2]

Semifinals
8–25 July
Final
6–8 August
Havana, Cuba
 Australia5
Mexico City, Mexico (clay)
 Cuba0
 Australia4
Montreal, Canada (grass)
 Mexico1
 Canada1
 Mexico4

Semifinals

Cuba vs. Australia


Cuba
0
Havana, Cuba[3]
23–25 July 1948

Australia
5
1 2 3 4 5
1 Cuba
Australia
Joffre Etcheverry
Adrian Quist
1
6
0
6
0
6
     
2 Cuba
Australia
José Agüero
Bill Sidwell
3
6
1
6
4
6
     
3 Cuba
Australia
José Agüero / Ricardo Morales
Colin Long / Bill Sidwell
5
7
2
6
3
6
     
4 Cuba
Australia
José Agüero
Adrian Quist
3
6
4
6
3
6
     
5 Cuba
Australia
Antonio Daly
Bill Sidwell
1
6
1
6
3
6
     

Canada vs. Mexico


Canada
1
Mount Royal Tennis Club, Montreal, Canada[4]
8–10 July 1948
Grass

Mexico
4
1 2 3 4 5
1 Canada
Mexico
Henri Rochon
Francisco Guerrero Arcocha
6
2
7
5
6
4
     
2 Canada
Mexico
Brendan Macken
Armando Vega
4
6
1
6
3
6
     
3 Canada
Mexico
Brendan Macken / James Macken
Gustavo Palafox / Armando Vega
2
6
3
6
4
6
     
4 Canada
Mexico
Henri Rochon
Armando Vega
2
6
1
6
3
6
     
5 Canada
Mexico
Walter Stohlberg
Francisco Guerrero Arcocha
10
12
1
6
2
6
     

Final

References

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