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1960 United States Senate election in Rhode Island

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The 1960 United States Senate election in Rhode Island took place on November 8, 1960. Incumbent Democratic U.S. Senator Theodore F. Green did not seek re-election. Democrat Claiborne Pell won the seat, defeating Republican Raoul Archambault Jr.

Quick facts Nominee, Party ...
1960 United States Senate election in Rhode Island

← 1954
November 8, 1960
1966 →
 
Nominee Claiborne Pell Raoul Archambault Jr.
Party Democratic Republican
Popular vote 275,575 124,408
Percentage 68.90% 31.10%

Pell:      50–60%      60–70%      70–80%      80–90%
Archambault:      50–60%      60–70%

U.S. senator before election

Theodore F. Green
Democratic

Elected U.S. Senator

Claiborne Pell
Democratic

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Primary elections

The Republican primary was held on September 19, 1960, and the Democratic primary was held on September 28, 1960.[1]

Democratic primary

Candidates

Results

More information Party, Candidate ...
Democratic primary results[3][4][5]
Party Candidate Votes %
Democratic Claiborne Pell 83,184 61.33%
Democratic Dennis J. Roberts 44,924 33.12%
Democratic J. Howard McGrath 7,535 5.56%
Total votes 135,643 100.00%
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Republican primary

Candidates

  • Raoul Archambault Jr., Republican nominee for Governor in 1952

Results

More information Party, Candidate ...
Republican primary results[4][6]
Party Candidate Votes %
Republican Raoul Archambault Jr. unopposed
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General election

Results

More information Party, Candidate ...
General election results [7][8][9][10]
Party Candidate Votes %
Democratic Claiborne Pell 275,575 68.90
Republican Raoul Archambault Jr. 124,408 31.10
Majority 151,167 37.80
Turnout 399,983
Democratic hold
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