1968 Missouri Attorney General election
From Wikipedia, the free encyclopedia
The 1968 Missouri Attorney General election was held on November 5, 1968, in order to elect the attorney general of Missouri. Republican nominee John Danforth defeated Democratic nominee and incumbent attorney general Norman H. Anderson.[1]
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November 5, 1968
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General election
On election day, November 5, 1968, Republican nominee John Danforth won the election by a margin of 72,133 votes against his opponent Democratic nominee Norman H. Anderson, thereby gaining Republican control over the office of attorney general. Danforth was sworn in as the 37th attorney general of Missouri on January 13, 1969.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | John Danforth | 891,498 | 52.11 | |
| Democratic | Norman H. Anderson (incumbent) | 819,365 | 47.89 | |
| Total votes | 1,710,863 | 100.00 | ||
| Republican gain from Democratic | ||||