1976 United States presidential election in Rhode Island

1976 United States presidential election in Rhode Island
← 1972 November 2, 1976 1980 →
Turnout	76.4%
Carter 40–50% 50–60% 60–70%	Ford 40–50% 50–60% 60–70%
President before election; Gerald Ford; Republican	Elected President ; Jimmy Carter; Democratic

The 1976 United States presidential election in Rhode Island took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

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Rhode Island was won by Jimmy Carter (D–Georgia), with 55.36% of the popular vote. Carter defeated incumbent President Gerald Ford (R–Michigan), who finished with 44.08% of the popular vote. No third-party candidate received any votes.

Party		Candidate	Votes	%
	Democratic	Jimmy Carter	227,636	55.36%
	Republican	Gerald Ford (inc.)	181,249	44.08%
	Write-In		2,285	0.56%
Total votes			411,170	100%

County	Jimmy Carter Democratic		Gerald Ford Republican		Various candidates Other parties		Margin		Total votes cast
County	#	%	#	%	#	%	#	%	Total votes cast
Bristol	11,228	52.41%	10,131	47.29%	66	0.30%	1,097	5.12%	21,425
Kent	35,855	51.07%	34,131	48.61%	227	0.32%	1,724	2.46%	70,213
Newport	17,768	53.67%	15,155	45.78%	184	0.55%	2,613	7.89%	33,107
Providence	144,805	57.96%	103,976	41.62%	1,036	0.42%	40,829	16.34%	249,817
Washington	17,980	49.91%	17,856	49.57%	186	0.52%	124	0.34%	36,022
Totals	227,636	55.36%	181,249	44.08%	2,285	0.56%	46,387	11.28%	411,170

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