1988 Big Ten Conference football season

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SportFootball
Teams10
ChampionsMichigan
1988 Big Ten Conference football season
LeagueNCAA Division I-A
SportFootball
Teams10
ChampionsMichigan
Football seasons
1988 Big Ten Conference football standings
Conf.Overall
TeamW L TW L T
No. 4 Michigan $ 7 0 19 2 1
Michigan State 6 1 16 5 1
Illinois 5 2 16 5 1
Iowa 4 1 36 4 3
No. 20 Indiana 5 3 08 3 1
Purdue 3 5 04 7 0
Ohio State 2 5 14 6 1
Northwestern 2 5 12 8 1
Wisconsin 1 7 01 10 0
Minnesota 0 6 22 7 2
  • $ Conference champion
Rankings from AP Poll

The 1988 Big Ten Conference football season was the 93rd season of college football played by the member schools of the Big Ten Conference and was a part of the 1988 NCAA Division I-A football season.

The No. 4 Michigan Wolverines won the 1988 Big Ten championship with a 7-0-1 conference mark (tying Iowa) and a trip to play USC in the Rose Bowl, winning that game 22-14.[1]

Michigan State came in second at 6-1-1 (6-5-1 overall), also tying Iowa. Illinois finished third at 5-2-1 (6-5-1 overall), tying Minnesota.

Iowa came in fourth with a 4-1-3 conference record, with their third tie coming against Ohio State. No. 20 Indiana finished in fifth place at 5-3 (8-3-1 overall).

Purdue was sixth at 3-5 (4-7 overall), while Ohio State and Northwestern tied for seventh place with 2-5-1 Big Ten records. Northwestern played Minnesota to a second tied game.

Wisconsin came in ninth place at 1-7 (1-10 overall) while Minnesota posted an 0-6-2 conference mark (2-7-2 overall).

With tie games being eliminated for the 1995 season's bowl games, the 1988 Big Ten season remains the most recent year that the conference had three or more league games end in a tie:

Bowl games

1989 NFL draft

References

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