1988 United States Senate election in Ohio

The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.^[1] Metzenbaum easily won the Democratic nomination with over 80% of the vote, while Cleveland Mayor George Voinovich was uncontested in his primary. This was the last time Democrats won this seat until 2006. Voinovich later served as Ohio's Governor from 1991 to 1998 and held the state's other U.S. Senate seat from 1999 to 2011. As of 2024^[update], 1988 remains the last time that Ohio voted for different parties in concurrent presidential and Senate elections.

Quick facts Nominee, Party ...

1988 United States Senate election in Ohio

← 1982 November 8, 1988 1994 →

Nominee Howard Metzenbaum George Voinovich Party Democratic Republican Popular vote 2,480,038 1,872,716 Percentage 56.97% 42.31%

County Results Township Results Metzenbaum:      50–60%      60–70%      70–80% Voinovich:      50–60%      60–70%

U.S. senator before election Howard Metzenbaum Democratic Elected U.S. Senator Howard Metzenbaum Democratic

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