1989 Asian Open
Snooker tournament
From Wikipedia, the free encyclopedia
The 1989 555 Asian Open was a professional ranking snooker tournament that took place between 17 and 27 August 1989 at the Channel 12 Studios in Bangkok, Thailand.[2][3]
| Tournament information | |
|---|---|
| Dates | 17–27 August 1989 |
| Venue | Channel 12 Studios |
| City | Bangkok |
| Country | Thailand |
| Organisation | WPBSA |
| Format | Ranking event |
| Total prize fund | £200,000[1] |
| Winner's share | £40,000[1] |
| Highest break |  Stephen Hendry (SCO) (140)[1] |
| Final | |
| Champion | Stephen Hendry (SCO) |
| Runner-up |  James Wattana (THA) |
| Score | 9–6 |
1990 → | |
Stephen Hendry won the tournament by defeating James Wattana 9–6 in the final.[4]
