2006 BCR Open Romania – Doubles

2006 tennis event results From Wikipedia, the free encyclopedia

The Men’s Doubles tournament of the 2006 BCR Open Romania tennis championship took place in Bucharest, Romania, between 11 and 17 September 2006. 16 pairs from 13 countries competed in the 4-round tournament.

Score6–7(5–7), 7–6(7–5), [10–8]
Draw16 (2WC)
Quick facts Doubles, Final ...
Doubles
2006 BCR Open Romania
Final
ChampionsPoland Mariusz Fyrstenberg
Poland Marcin Matkowski
Runners-upArgentina Martín García
Peru Luis Horna
Score6–7(5–7), 7–6(7–5), [10–8]
Details
Draw16 (2WC)
Seeds4
Events
Singles Doubles
 2005 ·
· 2007 
Close

José Acasuso and Sebastián Prieto were the defending champions, but Acasuso opted to rest in order to compete at the Davis Cup the following week. Prieto teamed up with František Čermák and lost in the quarterfinals to Martín García and Luis Horna.

Mariusz Fyrstenberg and Marcin Matkowski won the title by defeating García and Horna 6–7(5–7), 7–6(7–5), [10–8] in the final.[1]

Seeds

  1. Poland Mariusz Fyrstenberg / Poland Marcin Matkowski (champions)
  2. Austria Julian Knowle / Austria Jürgen Melzer (semifinals)
  3. Czech Republic František Čermák / Argentina Sebastián Prieto (quarterfinals)
  4. Germany Michael Kohlmann / Germany Alexander Waske (quarterfinals)

Draw

References

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