2018 Macau Masters
Snooker tournament
From Wikipedia, the free encyclopedia
The 2018 Macau Masters was a non-ranking team and six-red snooker invitational event that took place on 24 and 25 October 2018.[2] The event's team event was made up of two teams of four, competing in six games, with Team B defeating Team A with a score of 5–1.[3] The event's six red singles knockout tournament was won by Barry Hawkins.
| Tournament information | |
|---|---|
| Dates | 24–25 October 2018 |
| Venue | Ballroom, JW Marriott Hotel[1] |
| City | Macau |
| Country | China |
| Organisation | CBSA |
| Format | Non-ranking team & Six-red Snooker event |
| Highest break | |
| Final | |
| Champion | |
| Runner-up | |
| Score | 3–2 |
Prize Fund
Tournament teams
The event was made up of two teams of four, with players playing in six "best of 5" frames matches. Frames 1, 3 and 5 were doubles matches, whereas frames 2 and 4 were alternate singles.[5][6][7]
| Team | Player 1 | Player 2 | Player 3 | Player 4 |
|---|---|---|---|---|
| Team A | ||||
| Team B |
Results
Team event
The team event saw both teams field teams of two for individual team matches. Each player could only play with a partner for one match during the event.[8]
| Team A |
1–3 | Team B |
| 2–3 | ||
| 1–3 | ||
| 3–2 | ||
| 0–3 | ||
| 0–3 |
- Team result
- Team A 1–5 Team B
Six-red event
To finish the event, the Six-Red Leapfrog Challenge took place.[1] All 8-players played in a "killer" style match, with players required to win their match to continue on a winner stays on basis. The players were drawn based on world rankings.[9] All matches were first to one frame of 6-red snooker, with the final being a best of 5 frame 6-red match.[10]
| 1–0 | ||
| 1–0 | ||
| 1–0 | ||
| 1–0 | ||
| 1–0 | ||
| 1–0 |
| Final (Best of 5 frames) | ||
|---|---|---|
| Barry Hawkins | 3 – 2 |