2020 Sahrawi legislative election
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52 (of the 53) seats in the National Council 27 seats needed for a majority | ||||||||||||||||||||||||||||
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| Registered | ~100,000 | |||||||||||||||||||||||||||
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Legislative elections were held in the Sahrawi Republic on 8–9 March 2020[1] to elect 52 of the 53 members of the Sahrawi National Council, the unicameral parliament of the SADR. More than 100,000 Sahrawis were registered to vote, with 145 candidates contesting the elections.[2]
Legislative elections in the Sahrawi Republic are organised mainly using a single non-transferable vote, as Sahrawis get one vote by checking a box next to the face of the candidate in the ballot.[3] Members are elected for a three-year term by direct universal suffrage.[2]
35 seats are elected in constituencies based on the wilayas (or regions) that the Sahrawi refugee camps are divided in, while seven seats are elected in constituencies based on the seven military regions that the Sahrawi liberated territories are divided and another 3 are elected representing soldiers of the Sahrawi People's Liberation Army (EPLS) at large.
Three members are elected in representation of three branches of the Polisario Front: one representing the National Union of Sahrawi Women (UNMS), one representing the Sahrawi Youth Union (UJSARIO) and one representing the Sahrawi Trade Union (UGTSARIO). The final 5 seats are elected by members of the Consultative Council, a consultative body to the President of the SADR.[4]
Results
| Party | Seats | +/– | |
|---|---|---|---|
| Polisario Front | 53 | 0 | |
| Total | 53 | 0 | |
