2025 ATP Hong Kong Tennis Open – Doubles
2025 tennis event results
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Sander Arends and Luke Johnson defeated Karen Khachanov and Andrey Rublev in the final, 7–5, 6–4, [10–7] to win the doubles tennis title at the 2025 ATP Hong Kong Tennis Open.[1]
Champions
Sander Arends
Luke Johnson
Sander Arends 
Luke JohnsonRunners-up
Karen Khachanov
Andrey Rublev
Karen Khachanov Andrey RublevScore7–5, 4–6, [10–7]
Draw16 (2 WC )
| Doubles | |
|---|---|
| 2025 ATP Hong Kong Tennis Open | |
| Champions | Sander Arends Luke Johnson |
| Runners-up | Karen Khachanov Andrey Rublev |
| Score | 7–5, 4–6, [10–7] |
| Draw | 16 (2 WC ) |
| Seeds | 4 |
Marcelo Arévalo and Mate Pavić were the reigning champions,[2] but both players decided not to participate this year.
Seeds
Sadio Doumbia / Fabien Reboul (semifinals)
Adam Pavlásek / Jean-Julien Rojer (first round)
Skander Mansouri / 
Joran Vliegen (semifinals)
Yuki Bhambri / Albano Olivetti (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 |  S Doumbia F Reboul
| 6 | 6 | ||||||||||||||||||||||||
 R Carballés Baena A Müller
| 3 | 2 | 1 | S Doumbia F Reboul
| 6 | 6 | |||||||||||||||||||||
| WC |  Z Bergs L Tien
| 65 | 79 | [11] | WC | Z Bergs L Tien
| 3 | 2 | |||||||||||||||||||
 L Darderi C Norrie
| 77 | 67 | [9] | 1 | S Doumbia F Reboul
| 63 | 3 | ||||||||||||||||||||
| 4 |  Y Bhambri A Olivetti
| 6 | 5 | [10] | K Khachanov A Rublev
| 77 | 6 | ||||||||||||||||||||
 C Frantzen H Jebens
| 3 | 7 | [5] | 4 | Y Bhambri A Olivetti
| 4 | 65 | ||||||||||||||||||||
| K Khachanov A Rublev
| 6 | 6 | K Khachanov A Rublev
| 6 | 77 | ||||||||||||||||||||||
| WC |  J-s Nam C Wong
| 1 | 4 | K Khachanov A Rublev
| 5 | 6 | [7] | ||||||||||||||||||||
| A Davidovich Fokina A Fils
| 6 | 6 | S Arends L Johnson
| 7 | 4 | [10] | |||||||||||||||||||||
| P Martínez J Munar
| 2 | 1 | A Davidovich Fokina A Fils
| ||||||||||||||||||||||||
| Alt |  G Diallo F Passaro
| 3 | 64 | 3 |  S Mansouri J Vliegen
| w/o | |||||||||||||||||||||
| 3 | S Mansouri J Vliegen
| 6 | 77 | 3 | S Mansouri J Vliegen
| 6 | 3 | [5] | |||||||||||||||||||
| L Musetti L Sonego
| 6 | 4 | [7] | S Arends L Johnson
| 2 | 6 | [10] | ||||||||||||||||||||
 S González L Miedler
| 4 | 6 | [10] | S González L Miedler
| 62 | 5 | |||||||||||||||||||||
| S Arends L Johnson
| 5 | 6 | [10] | S Arends L Johnson
| 77 | 7 | |||||||||||||||||||||
| 2 |  A Pavlásek J-J Rojer
| 7 | 3 | [5] | |||||||||||||||||||||||