Antioch Township, White County, Arkansas
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Antioch Township | |
|---|---|
  Antioch Township Location in Arkansas  Antioch Township Antioch Township (the United States) | |
| Coordinates: 35°08′28″N 91°56′25″W / 35.141235°N 91.940339°W[1] | |
| Country | United States |
| State | Arkansas |
| County | White |
| Area | |
• Total | 14.880 sq mi (38.54 km2) |
| • Land | 14.880 sq mi (38.54 km2) |
| • Water | 0.000 sq mi (0 km2) |
| Elevation | 400 ft (120 m) |
| Population | |
• Total | 562 |
| • Density | 37.8/sq mi (14.6/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code[2][3] | 05-90042 |
| GNIS ID[2][3] | 69814 |
Antioch Township is a township in White County, Arkansas, United States.[4] Its total population was 562 as of the 2010 United States census,[1][5] an increase of 15.4 percent from 487 at the 2000 census.[6][7]
According to the 2010 Census, Antioch Township is located at 35°08′28″N 91°56′25″W / 35.141235°N 91.940339°W (35.141235, -91.940339).[1] It has a total area of 14.880 square miles (38.54 square kilometers), all of which is land.[1] As per the USGS National Elevation Dataset, the elevation is 400 feet (122 m).[2]
