Benton Township, Elkhart County, Indiana

Township in Indiana, United States From Wikipedia, the free encyclopedia

Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2020 census, its population was 3,200, up from 2,963 at the previous census.[3]

CountryUnited States
Elevation850 ft (260 m)
FIPS code18-04798[2]
Quick facts Country, State ...
Benton Township
Location of Benton Township in Elkhart County
Location of Benton Township in Elkhart County
Coordinates: 41°28′55″N 85°42′27″W
CountryUnited States
StateIndiana
CountyElkhart
Government
  TypeIndiana township
Area
  Total
35.9 sq mi (93 km2)
  Land35.84 sq mi (92.8 km2)
  Water0.06 sq mi (0.16 km2)
Elevation850 ft (260 m)
Population
 (2020)
  Total
3,200
  Density89/sq mi (34/km2)
FIPS code18-04798[2]
GNIS feature ID453105
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According to the 2020 "ACS 5-Year Estimates Data Profiles", 70.1% of the township's population spoke only English, while 23.7 spoke an "other [than Spanish] Indo-European language"[4] (basically Pennsylvania German/German).

Geography

According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.84 square miles (92.8 km2) (or 99.83%) is land and 0.06 square miles (0.16 km2) (or 0.17%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Brown and Hire.

Demographics

More information Census, Pop. ...
Historical population
CensusPop.Note
20102,963
20203,2008.0%
U.S. Censuses: 2010,[3]
and 2020[4]
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References

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