Bifolium

Given a circle C through a point O, and line L tangent to the circle at point O: for each point Q on C, define the point P such that PQ is parallel to the tangent line L, and PQ = OQ. The collection of points P forms the bifolium.^[1]

In polar coordinates, the bifolium's equation is

${\displaystyle \rho =a\sin \theta \cdot \cos ^{2}\theta ,}$

while (first eqn.)

${\displaystyle \rho ^{2\cdot 2}=a\cdot x^{2}y,\,\,\rho ^{2}=\pm x\cdot (ay)^{1/2}.}$

For a = 1, the total included area is approximately 0.10.

• Folium of Descartes
• Trifolium curve