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Bovina, Wisconsin

Town in Wisconsin, United States From Wikipedia, the free encyclopedia

Bovina is a town in Outagamie County, Wisconsin, United States. At the 2020 census, the town had a total population of 1,153.[3] The village of Shiocton is located within the town.

Elevation764 ft (233 m)
FIPS code55-08975[2]
Quick facts Country, State ...
Bovina, Wisconsin
Location of Bovina, within Outagamie County
Location of Bovina, within Outagamie County
Coordinates: 44°27′26″N 88°33′43″W
Country United States
State Wisconsin
CountyOutagamie
Area
 • Total
33.7 sq mi (87.4 km2)
 • Land33.7 sq mi (87.2 km2)
 • Water0.077 sq mi (0.2 km2)
Elevation764 ft (233 m)
Population
 (2020)
 • Total
1,153
 • Density34.2/sq mi (13.2/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
FIPS code55-08975[2]
GNIS feature ID1582846[1]
Websitehttps://tn.bovina.wi.gov/
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Geography

According to the United States Census Bureau, the town has a total area of 33.7 square miles (87.4 km2), of which 33.7 square miles (87.2 km2) is land and 0.1 square mile (0.2 km2) (0.18%) is water.

Demographics

At the 2020 census, there were 1,153 people and 402 households.[4] There were 483 housing units. The racial makeup of the town was 1,078 White, 6 black or African descent, 1 American Indian, 11 Asian, 43 Hispanic, and 10 from some other races .[5]

Of 402 households, 21.7% had children under the age of 18 living with their families, 69.7% had married couples living together, 7.5% had a female householder with no husband present, and 16.7% had a male householder with no female present. 13.5% of all households were made up of individuals 65 or older. The average family size was 2.99.[4]

The Median Household Income was $77,917 and the Employment Rate was at 62.0%. Approximately 18.5% of residents have a Bachelor's Degree or Higher.[4]

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