Bradwell Bay Wilderness
From Wikipedia, the free encyclopedia
| Bradwell Bay Wilderness | |
|---|---|
  Location in Florida  Location in United States | |
| Location | Wakulla County, Florida, USA |
| Nearest city | Sopchoppy, Florida |
| Coordinates | 30°10′44″N 84°33′28″W / 30.178812°N 84.5576836°W |
| Area | 24,602 acres (9,956 ha) |
| Established | 3 January 1975[2] |
| Governing body | US Forest Service |
The Bradwell Bay Wilderness is part of the United States National Wilderness Preservation System, located in the Florida panhandle adjacent to the Apalachicola National Forest. The 24,602 acre (100 km2) wilderness was established on 3 January 1975 by the Eastern Wilderness Act. "Bay" in this case means "a recess of land, partly surrounded by hills", which, in this particular instance, is mostly titi swamp and standing water. The Sopchoppy River marks the Bradwell Bay's eastern edge.
A section of the Florida Trail, which usually requires wading through swampy terrain, passes through the wilderness.[3]
Titi trees, longleaf pines, loblolly pine and wire grass make up much of the swamp. The wilderness also contains a 100 acres (40 ha) old-growth slash pine - swamp black gum swamp.[4]
