Bromine(I) fluorosulfonate
Chemical compound
From Wikipedia, the free encyclopedia
Bromine(I) fluorosulfonate is an inorganic compound of bromine, sulfur, fluorine, and oxygen with the chemical formula BrSO3F. This is a monovalent compound of bromine from the group of fluorosulfonates.
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| Names | |
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| Other names
Bromine(I) fluorosulfate,[1] bromine fluorosulfate | |
| Identifiers | |
3D model (JSmol) |
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| ChemSpider | |
PubChem CID |
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| Properties | |
| BrFO3S | |
| Molar mass | 178.96 g·mol−1 |
| Appearance | blackish-red liquid |
| Density | 2.60 g/cm3 |
| Boiling point | 120.5 °C |
| reacts with water | |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Synthesis
Similarly with other halogenofluorosulfonates, the reaction of bromine with peroxydisulfuryl difluoride produces the compound:[2][3]
- Br2 + S2O6F2 → 2BrSO3F
The reduction of bromine(III) fluorosulfonate also yields bromine(I) fluorosulfonate:[4]
- Br(SO3F)3 + Br2 → 3BrSO3F
Chemical properties
Bromo(I) fluorosulfonate is a blackish-red, viscous, hydrolysis-sensitive liquid that reacts violently with water. Upon cooling, it solidifies into a glassy state.
Bromo(I) fluorosulfonate reacts with iodine(I) fluorosulfonate at temperatures above 50 °C to form dibromoiodofluorosulfonate:[5]
- 2BrSO3F + ISO3F → IBr2(SO3F)3