Conway triangle notation

Given a reference triangle whose sides are a, b and c and whose corresponding internal angles are A, B, and C then the Conway triangle notation is simply represented as follows: $${\displaystyle S=bc\sin A=ac\sin B=ab\sin C,}$$ where^[3][4] $${\displaystyle {\begin{aligned}S&=2\times {\text{reference triangle area}},\\[2pt]S_{\varphi }&=S\cot \varphi .\end{aligned}}}$$

In particular: $${\displaystyle {\begin{aligned}S_{A}&=S\cot A=bc\cos A={\frac {b^{2}+c^{2}-a^{2}}{2}},\\[2pt]S_{B}&=S\cot B=ac\cos B={\frac {a^{2}+c^{2}-b^{2}}{2}},\\[2pt]S_{C}&=S\cot C=ab\cos C={\frac {a^{2}+b^{2}-c^{2}}{2}},\\[2pt]S_{\omega }&=S\cot \omega ={\frac {a^{2}+b^{2}+c^{2}}{2}},\end{aligned}}}$$

where ω is the Brocard angle. The law of cosines is used: ${\displaystyle a^{2}=b^{2}+c^{2}-2bc\cos A.}$

Third-, double-, and half-angle identities: $${\displaystyle {\begin{aligned}S_{\frac {\pi }{3}}&=S\cot {\frac {\pi }{3}}=S{\frac {\sqrt {3}}{3}}\\[2pt]S_{2\varphi }&={\frac {S_{\varphi }^{2}-S^{2}}{2S_{\varphi }}}\\[2pt]S_{\frac {\varphi }{2}}&=S_{\varphi }+{\sqrt {S_{\varphi }^{2}+S^{2}}}\end{aligned}}}$$

for values of φ where 0 < φ < π,

$${\displaystyle {\begin{aligned}S_{\vartheta +\varphi }&={\frac {S_{\vartheta }S_{\varphi }-S^{2}}{S_{\vartheta }+S_{\varphi }}},\\[2pt]S_{\vartheta -\varphi }&={\frac {S_{\vartheta }S_{\varphi }+S^{2}}{S_{\varphi }-S_{\vartheta }}}.\end{aligned}}}$$

Furthermore the convention uses a shorthand notation for ${\displaystyle S_{\vartheta }S_{\varphi }=S_{\vartheta \varphi },}$ and ${\displaystyle S_{\vartheta }S_{\varphi }S_{\psi }=S_{\vartheta \varphi \psi }.}$

$${\displaystyle {\begin{aligned}\sin A&={\frac {S}{bc}}={\frac {S}{\sqrt {S_{A}^{2}+S^{2}}}}\\[2pt]\cos A&={\frac {S_{A}}{bc}}={\frac {S_{A}}{\sqrt {S_{A}^{2}+S^{2}}}}\\[2pt]\tan A&={\frac {S}{S_{A}}}\\[6pt]a^{2}&=S_{B}+S_{C}\\[2pt]b^{2}&=S_{A}+S_{C}\\[2pt]c^{2}&=S_{A}+S_{B}\end{aligned}}}$$

$${\displaystyle {\begin{aligned}\sum _{\text{cyclic}}S_{A}&=S_{A}+S_{B}+S_{C}=S_{\omega }\\[2pt]S^{2}&=b^{2}c^{2}-S_{A}^{2}=a^{2}c^{2}-S_{B}^{2}=a^{2}b^{2}-S_{C}^{2}\\[6pt]S_{BC}&=S_{B}S_{C}=S^{2}-a^{2}S_{A}\\[2pt]S_{AC}&=S_{A}S_{C}=S^{2}-b^{2}S_{B}\\[2pt]S_{AB}&=S_{A}S_{B}=S^{2}-c^{2}S_{C}\\[8pt]S_{ABC}&=S_{A}S_{B}S_{C}=S^{2}(S_{\omega }-4R^{2})\\[8pt]S_{\omega }&=s^{2}-r^{2}-4rR\end{aligned}}}$$

where

R is the circumradius

r is the incenter

${\displaystyle abc=2SR}$

${\displaystyle s={\frac {a+b+c}{2}}}$

${\displaystyle {\frac {S}{r}}=a+b+c}$

$${\displaystyle {\begin{aligned}\sin A\sin B\sin C&={\frac {S}{4R^{2}}}\\[2pt]\cos A\cos B\cos C&={\frac {S_{\omega }-4R^{2}}{4R^{2}}}\end{aligned}}}$$

$${\displaystyle {\begin{aligned}\sum _{\text{cyclic}}\sin A&={\frac {S}{2Rr}}={\frac {s}{R}}\\[2pt]\sum _{\text{cyclic}}\cos A&={\frac {r+R}{R}}\\[2pt]\sum _{\text{cyclic}}\tan A&={\frac {S}{S_{\omega }-4R^{2}}}=\tan A\tan B\tan C\end{aligned}}}$$

$${\displaystyle {\begin{array}{ll}\displaystyle \sum _{\text{cyclic}}a^{2}S_{A}\!\!&=&a^{2}S_{A}+b^{2}S_{B}+c^{2}S_{C}=2S^{2}\\[2pt]\displaystyle \sum _{\text{cyclic}}a^{4}&=&2(S_{\omega }^{2}-S^{2})\\[2pt]\displaystyle \sum _{\text{cyclic}}S_{A}^{2}&=&S_{\omega }^{2}-2S^{2}\\[2pt]\displaystyle \sum _{\text{cyclic}}S_{BC}&=&\displaystyle \sum _{\text{cyclic}}S_{B}S_{C}=S^{2}\\[2pt]\displaystyle \sum _{\text{cyclic}}b^{2}c^{2}&=&S_{\omega }^{2}+S^{2}\end{array}}}$$

Let D be the distance between two points P and Q whose trilinear coordinates are $${\displaystyle {\begin{aligned}P=p_{a}:p_{b}:p_{c},\\Q=q_{a}:q_{b}:q_{c}.\end{aligned}}}$$ Let $${\displaystyle {\begin{aligned}K_{p}&=ap_{a}+bp_{b}+cp_{c},\\K_{q}&=aq_{a}+bq_{b}+cq_{c}.\end{aligned}}}$$ Then D is given by the formula:^[5] $${\displaystyle D^{2}=\sum _{\text{cyclic}}a^{2}S_{A}\left({\frac {p_{a}}{K_{p}}}-{\frac {q_{a}}{K_{q}}}\right)^{2}}$$

• Brocard angle
• Orthocenter
• Circumcenter
• Trilinear coordinates