Recall[2]: 59 that the Steenrod algebra
(also denoted
) is a graded noncommutative Hopf algebra which is cocommutative, meaning its comultiplication is cocommutative. This implies if we take the dual Hopf algebra, denoted
, or just
, then this gives a graded-commutative algebra which has a noncommutative comultiplication. We can summarize this duality through dualizing a commutative diagram of the Steenrod's Hopf algebra structure:

If we dualize we get maps

giving the main structure maps for the dual Hopf algebra. It turns out there's a nice structure theorem for the dual Hopf algebra, separated by whether the prime is
or odd.
In this case, the dual Steenrod algebra is a graded commutative polynomial algebra
where the degree
. Then, the coproduct map is given by

sending

where
.
For all other prime numbers, the dual Steenrod algebra is slightly more complex and involves a graded-commutative exterior algebra in addition to a graded-commutative polynomial algebra. If we let
denote an exterior algebra over
with generators
and
, then the dual Steenrod algebra has the presentation
![{\displaystyle {\mathcal {A}}_{*}=\mathbb {Z} /p[\xi _{1},\xi _{2},\ldots ]\otimes \Lambda (\tau _{0},\tau _{1},\ldots )}](https://wikimedia.org/api/rest_v1/media/math/render/svg/5ff4d1212b9e1b856bf52fb22caafb66f1e5221e)
where

In addition, it has the comultiplication
defined by

where again
.
The rest of the Hopf algebra structures can be described exactly the same in both cases. There is both a unit map
and counit map 

which are both isomorphisms in degree
: these come from the original Steenrod algebra. In addition, there is also a conjugation map
defined recursively by the equations

In addition, we will denote
as the kernel of the counit map
which is isomorphic to
in degrees
.