Dutch Hill (Herkimer County, New York)
From Wikipedia, the free encyclopedia
Mountain in New York, United States
Elevation1,043 feet (318 m)
| Dutch Hill | |
|---|---|
  Dutch Hill Location of Dutch Hill within New York Show map of New York Dutch Hill Dutch Hill (the United States) Show map of the United States | |
| Highest point | |
| Elevation | 1,043 feet (318 m) |
| Coordinates | 43°03′37″N 75°07′38″W / 43.06028°N 75.12722°W / 43.06028; -75.12722[1] |
| Geography | |
| Location | WNW of Frankfort, New York, U.S. |
| Topo map | USGS Utica East |
Dutch Hill is a mountain located in Central New York Region of New York located in the Town of Frankfort in Herkimer County, west-northwest of Frankfort.
- ↑ "Dutch Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved December 8, 2017.