First variation

Compute the first variation of

${\displaystyle J(y)=\int _{a}^{b}yy'\mathrm {d} x.}$

From the definition above:

${\displaystyle {\begin{aligned}\delta J(y,h)&=\left.{\frac {\mathrm {d} }{\mathrm {d} \varepsilon }}J(y+\varepsilon h)\right|_{\varepsilon =0}\\&=\left.{\frac {\mathrm {d} }{\mathrm {d} \varepsilon }}\int _{a}^{b}(y+\varepsilon h)(y^{\prime }+\varepsilon h^{\prime })\ \mathrm {d} x\right|_{\varepsilon =0}\\&=\left.{\frac {\mathrm {d} }{\mathrm {d} \varepsilon }}\int _{a}^{b}(yy^{\prime }+y\varepsilon h^{\prime }+y^{\prime }\varepsilon h+\varepsilon ^{2}hh^{\prime })\ \mathrm {d} x\right|_{\varepsilon =0}\\&=\left.\int _{a}^{b}{\frac {\mathrm {d} }{\mathrm {d} \varepsilon }}(yy^{\prime }+y\varepsilon h^{\prime }+y^{\prime }\varepsilon h+\varepsilon ^{2}hh^{\prime })\ \mathrm {d} x\right|_{\varepsilon =0}\\&=\left.\int _{a}^{b}(yh^{\prime }+y^{\prime }h+2\varepsilon hh^{\prime })\ \mathrm {d} x\right|_{\varepsilon =0}\\&=\int _{a}^{b}(yh^{\prime }+y^{\prime }h)\ \mathrm {d} x\\\end{aligned}}}$

• Calculus of variations
• Functional derivative
• Second variation