Fish curve

For an ellipse with the parametric equations $${\displaystyle \textstyle {x=a\cos(t),\qquad y={\frac {a\sin(t)}{\sqrt {2}}}},}$$ the corresponding fish curve has parametric equations $${\displaystyle \textstyle {x=a\cos(t)-{\frac {a\sin ^{2}(t)}{\sqrt {2}}},\qquad y=a\cos(t)\sin(t)}.}$$

When the origin is translated to the node (the crossing point), the Cartesian equation can be written as:^[2][3] $${\displaystyle \left(2x^{2}+y^{2}\right)^{2}-2{\sqrt {2}}ax\left(2x^{2}-3y^{2}\right)+2a^{2}\left(y^{2}-x^{2}\right)=0.}$$

The area of a fish curve is given by: $${\displaystyle {\begin{aligned}A&={\frac {1}{2}}\left|\int {\left(xy'-yx'\right)dt}\right|\\&={\frac {1}{8}}a^{2}\left|\int {\left[3\cos(t)+\cos(3t)+2{\sqrt {2}}\sin ^{2}(t)\right]dt}\right|,\end{aligned}}}$$ so the area of the tail and head are given by: $${\displaystyle {\begin{aligned}A_{\text{Tail}}&=\left({\frac {2}{3}}-{\frac {\pi }{4{\sqrt {2}}}}\right)a^{2},\\A_{\text{Head}}&=\left({\frac {2}{3}}+{\frac {\pi }{4{\sqrt {2}}}}\right)a^{2},\end{aligned}}}$$ giving the overall area for the fish as:^[2] $${\displaystyle A={\frac {4}{3}}a^{2}.}$$

The arc length of the curve is given by $${\displaystyle a{\sqrt {2}}\left({\frac {1}{2}}\pi +3\right).}$$

The curvature of a fish curve is given by: $${\displaystyle K(t)={\frac {2{\sqrt {2}}+3\cos(t)-\cos(3t)}{2a\left[\cos ^{4}t+\sin ^{2}t+\sin ^{4}t+{\sqrt {2}}\sin(t)\sin(2t)\right]^{\frac {3}{2}}}},}$$ and the tangential angle is given by: $${\displaystyle \phi (t)=\pi -\arg \left({\sqrt {2}}-1-{\frac {2}{\left(1+{\sqrt {2}}\right)e^{it}-1}}\right),}$$ where ${\displaystyle \arg(z)}$ is the complex argument.