Folkman graph

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Folkman graph
Drawing following Folkman (1967), Figure 1
Named afterJon Folkman
Vertices20
Edges40
Radius3
Diameter4
Girth4
Automorphisms5! · 25 = 3840
Chromatic number2
Chromatic index4
Genus3
Book thickness3
Queue number2
Properties
Table of graphs and parameters

In the mathematical field of graph theory, the Folkman graph is a 4-regular graph with 20 vertices and 40 edges. It is a regular bipartite graph with symmetries taking every edge to every other edge, but the two sides of its bipartition are not symmetric with each other, making it the smallest possible semi-symmetric graph.[1] It is named after Jon Folkman, who constructed it for this property in 1967.[2]

The Folkman graph can be constructed either using modular arithmetic or as the subdivided double of the five-vertex complete graph. Beyond the investigation of its symmetry, it has also been investigated as a counterexample for certain questions of graph embedding.

Semi-symmetric graphs are defined as regular graphs (that is, graphs in which all vertices touch equally many edges) in which each two edges are symmetric to each other, but some two vertices are not symmetric. Jon Folkman was inspired to define and research these graphs in a 1967 paper, after seeing an unpublished manuscript by E. Dauber and Frank Harary which gave examples of graphs meeting the symmetry condition but not the regularity condition. Folkman's original construction of this graph was a special case of a more general construction of semi-symmetric graphs using modular arithmetic, based on a prime number congruent to 1 mod 4. For each such prime, there is a number such that mod , and Folkman uses modular arithmetic to construct a semi-symmetric graph with vertices. The Folkman graph is the result of this construction for and .[2]

Construction of the Folkman graph from the complete graph . The green vertices subdivide each edge of , and the red pairs of vertices are the result of doubling the five vertices of .

Another construction for the Folkman graph begins with the complete graph on five vertices, . A new vertex is placed on each of the ten edges of , subdividing each edge into a two-edge path. Then, each of the five original vertices of is doubled, replacing it by two vertices with the same neighbors. The ten subdivision vertices form one side of the bipartition of the Folkman graph, and the ten vertices in twin pairs coming from the doubled vertices of form the other side of the bipartition.[3][4]

Because each edge of the result comes from a doubled half of an edge of , and because has symmetries taking every half-edge to every other half-edge, the result is edge-transitive. It is not vertex-transitive, because the subdivision vertices are not twins with any other vertex, making them different from the doubled vertices coming from .[3] Every 4-regular semi-symmetric graph in which some two vertices have the same neighborhood can be constructed in the same way, by subdividing and then doubling a 4-regular symmetric graph such as or the graph of the octahedron. However, there also exist larger 4-regular semi-symmetric graphs that do not have any twin vertices.[4][5]

Algebraic properties

Other properties

References

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