Frascarolo
Comune in Lombardy, Italy
From Wikipedia, the free encyclopedia
Frascarolo is a comune (municipality) in the Province of Pavia in the Italian region Lombardy, located about 60 km southwest of Milan and about 40 km southwest of Pavia. As of 31 December 2004, it had a population of 1,277 and an area of 23.4 km2.[3]
Frascarolo | |
|---|---|
| Comune di Frascarolo | |
| Coordinates: 45°3′N 8°41′E | |
| Country | Italy |
| Region | Lombardy |
| Province | Province of Pavia (PV) |
| Area | |
• Total | 23.4 km2 (9.0 sq mi) |
| Population (Dec. 2004)[2] | |
• Total | 1,277 |
| • Density | 54.6/km2 (141/sq mi) |
| Time zone | UTC+1 (CET) |
| • Summer (DST) | UTC+2 (CEST) |
| Postal code | 27030 |
| Dialing code | 0384 |
Frascarolo borders the following municipalities: Bassignana, Gambarana, Mede, Suardi, Torre Beretti e Castellaro, Valenza.
Demographic evolution
