Greenville (CDP), Greene County, New York

From Wikipedia, the free encyclopedia

CountryUnited States
Elevation709 ft (216 m)
Greenville, Greene County,
New York
Greenville is located in New York
Greenville
Greenville
Greenville is located in the United States
Greenville
Greenville
Coordinates: 42°24′55″N 074°01′19″W / 42.41528°N 74.02194°W / 42.41528; -74.02194[1]
CountryUnited States
StateNew York
CountyGreene County
TownGreenville
Area
  Total
3.92 sq mi (10.16 km2)
  Land3.88 sq mi (10.05 km2)
  Water0.042 sq mi (0.11 km2)
Elevation709 ft (216 m)
Population
 (2020)
  Total
688
  Density177.3/sq mi (68.45/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
ZIP code[3]
12083
Area code518
FIPS code[4]36-30609
GNIS feature ID[1]951773

Greenville is a hamlet and census-designated place (CDP) in the town of Greenville, in Greene County, New York, United States. The population of the CDP was 688 at the 2020 census, out of a total 3,741 people in the town as a whole.[5][6][7]

Greenville is located in northern Greene County at 42°24′55″N 074°01′19″W / 42.41528°N 74.02194°W / 42.41528; -74.02194 (42.4153596, -74.0220769), in the north-central part of the town of Greenville. Its elevation is 709 feet (216 m) above sea level.[1]

New York State Route 32 passes through the center of the hamlet, leading northeast 26 miles (42 km) to Albany and south 10 miles (16 km) to Cairo. New York State Route 81 leads west from Greenville 10 miles (16 km) to Cooksburg.

According to the United States Census Bureau, the Greenville CDP has a total area of 3.452 square miles (8.94 km2), of which 3.432 square miles (8.89 km2) is land and 0.020 square miles (0.05 km2), or 0.58%, is water.[4]

Demographics

References

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