Greigsville, New York

Census-designated place in New York, United States From Wikipedia, the free encyclopedia

Greigsville is a hamlet and census-designated place (CDP) in the town of York, Livingston County, New York, United States. As of the 2020 census, Greigsville had a population of 191.[3] The community is located at the intersection of New York State Route 36 and New York State Route 63.

CountryUnited States
Elevation
751 ft (229 m)
Quick facts Country, State ...
Greigsville, New York
Greigsville is located in New York
Greigsville
Greigsville
Greigsville is located in the United States
Greigsville
Greigsville
Coordinates: 42°49′50″N 77°53′49″W
CountryUnited States
StateNew York
CountyLivingston
TownYork
Area
  Total
0.71 sq mi (1.84 km2)
  Land0.71 sq mi (1.84 km2)
  Water0 sq mi (0.00 km2)
Elevation
751 ft (229 m)
Population
 (2020)
  Total
191
  Density269/sq mi (103.8/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
ZIP Code
14533 (Piffard)
Area code585
GNIS feature ID951801[2]
FIPS code36-30807
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Geography

Greigsville is in northwestern Livingston County, in the southern part of the town of York. It is bordered to the south by Wadsworth, and Retsof is less than 1 mile (1.6 km) to the east. State Route 36 leads north 3 miles (5 km) to York hamlet and south 4 miles (6 km) to Leicester, while SR 63 leads southeast 5.5 miles (8.9 km) to Geneseo, the Livingston county seat, and northwest 19 miles (31 km) to Batavia.

According to the U.S. Census Bureau, the Greigsville CDP has an area of 0.71 square miles (1.8 km2), all land.[4] The northeast border of the CDP follows Bidwells Creek, an eastward-flowing tributary of the Genesee River.

Demographics

More information Census, Pop. ...
Historical population
CensusPop.Note
2020191
U.S. Decennial Census[5]
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References

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