Groveland, Idaho
From Wikipedia, the free encyclopedia
Groveland, Idaho | |
|---|---|
Location of Groveland in Bingham County, Idaho. | |
| Coordinates: 43°13′25″N 112°22′16″W / 43.22361°N 112.37111°W | |
| Country | United States |
| State | Idaho |
| County | Bingham |
| Area | |
• Total | 2.297 sq mi (5.95 km2) |
| • Land | 2.297 sq mi (5.95 km2) |
| • Water | 0 sq mi (0 km2) |
| Elevation | 4,492 ft (1,369 m) |
| Population (2020) | |
• Total | 982 |
| • Density | 428/sq mi (165/km2) |
| Time zone | UTC-7 (Mountain (MST)) |
| • Summer (DST) | UTC-6 (MDT) |
| Area codes | 208, 986 |
| GNIS feature ID | 2585572[1] |
Groveland is a census-designated place in Bingham County, Idaho, United States. Its population was 982 as of the 2020 census.[2]
The community was named for the groves of trees near the original town site.[3]
